If the zeroes of x2+ax+b have opposite signs but equal magnitude, then
linear term doesn’t exist & b<0
a+b=0
a-b=0
linear term doesn’t exist & b>0
(x-a)(x+a) = x2−a2, Hence there’s no linear term
A matrix ‘B’ is singular if
If (ax − b) is factor of p(x), then
If the zeroes of ax2+bx+c are equal then
If the line ax + by + c=0 is a normal to the curve xy=1, then