Given polynomial is 2x³-15x²+37x-30 = 0
Given zeroes of polynomial arre in AP
Let zeroes of polynomials are : a-b, a, a+b
Comparing the given polynomial with Ax³+Bx²+Cx+D = 0
here A = 2 , B = -15 ,C=37 and D = -30
As we know that Sum of zero's = - B/A
a-b+a+a+b = - (-15)/2
3a = 15/2
a =5/2
Product of Zeros = -D/A
(a-b)a(a+b) = - (-30)/2
a[a²-b²] = 15
Substituting the value of a in above equation, we get the value of b
[5/2][(5/2)²-b²] = 15
(25/4)- b² = 6
25-4b² =6*4
-4b² = 24-25
-4b² = -1
b² = 1/4
b= ±1/2
Zero's of polynomials are : a-b , a, a+b =5/2-1/2 , 5/2 , 5/2+1/2
=4/2 , 5/2, 6/2
=2, 5/2 ,3
Answer : Zeroes of polynomial are 2, 5/2 ,3 with a = 2 and d = 1/2