1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# If the zeros of the polynomial x3−3x2+x+1 are a−b,a,a+b, then the value of a+b is

A
2+1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
12
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
31
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Either a or b
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct options are B √2+1 C 1−√2Comparing the given polynomial x3−3x2+x+1 with Ax3+Bx2+Cx+D. we getA=1,B=−3,C=1,D=1Here, the zeros of the given polynomial are a−b,a,a+b.Sum of zeros=−BA=−−31=3∴a−b+a+a+b=3.⇒3a=3.⇒a=1.Product of zeros=−DA=−11=−1∴(a−b)(a)(a+b)=−1.⇒a(a2−b2)=−1.since, a=1⇒(12−b2)=−1.⇒b2=2⇒b=√2 or −√2value of a+b=√2+1 or 1−√2

Suggest Corrections
1
Join BYJU'S Learning Program
Related Videos
Relationship between Zeroes and Coefficients of a Polynomial
MATHEMATICS
Watch in App
Join BYJU'S Learning Program