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Question

If , then find the least positive integral value of m .

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Solution

It is given that,

( 1+i 1i ) m =1

Rationalize the denominator,

( 1+i 1i × 1+i 1+i ) m =1 ( ( 1+i ) 2 1 2 i 2 ) m =1 ( 1+ i 2 +2i 1+1 ) m =1 ( 11+2i 2 ) m =1

Simplify further,

( i ) m = ( i ) 4 m=4

Therefore, the least integral value of m is 4.


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