Question

If there are $N$ nuclear particles in a nucleus of radius $R$ then the number of nuclear particles in radius $3R$ will be

• A. $N$
• B. $2N$
• C. $27N$
• D. $\frac{21}{3}N$

Answer 1

The correct option is C $27N$

Volume of nucleus depends on $R^3$

So, for radius $3R$ and volume will become $27$ times of initial value.

So, the number of nuclear particle $=27N$