If there are no heat losses, the heat released by the condensation of x gm of steam at 100∘C into water at 100∘C can be used to convert y gm of ice at 0°C into water at 100∘C. Then the ratio y : x is nearly
3 : 1
Heat released to convert x gm of steam at 100∘C to water at 100∘C=x×540 cals.
If y gm of ice is converted from 0∘C to water at 100∘C it requires heat y×80+y×1×100=180y
∴x×540=180y or yx=540180=31