Question

If there are no heat losses, the heat released by the condensation of x grams of steam at ${100}^{o}C$ into water at ${100}^{o}C$ converts y grams of ice of $0^{o}C$ into water at ${100}^{o}C$. Find the ratio of y to x.

• A. 2 : 1
• B. 3 : 1
• C. 3 : 2
• D. 4 : 1

Answer 1

Answer: (B)

3 : 1

Heat lost by 'x' g of steam at ${100}^{o}C$ to water at ${100}^{o}C=x\left(540\right)=540x......\left(1\right)$
Heat required by 'y' g of ice at $0^{o}C$ into water at ${100}^{o}C$
$=(y\times 80)+(y\times 1\times 100)$
$=180y.......\left(2\right)$
Given $1=2$
$\therefore 540x=180y$
$=\frac{y}{x}=\frac{540}{180}$
$=\frac{y}{x}=3:1$