Question

If there are three possible values $(-1/2,0,+1/2)$ for the spin quantum number, then the maximum capacity of the second orbit will become of:

• A. $8$ electrons
• B. $6$ electrons
• C. $12$ electrons
• D. $27$ electrons

Answer 1

The correct option is C $12$ electrons

If there are three possible values $(+1/2,0,-1/2)$ for the spin quantum, then electronic configuration of will be:

$1s^3,2s^3,2p^9,3s^3$ and so...on

$1s,2sand3s$ orbitals will have $3$ electrons each instead of $2$ electrons.

$2p$ and $3p$ orbitals will have $9$ electrons each instead of $6$ electrons.

So, $1^{st}$ orbit will occupy $3$ electrons, $2^{nd}$ orbit will occupy $3+9=12$ electrons

Hence option C is correct