If there are two sets A and B such that n A - B - n A - B - Universal set contains - x - elements- Then n A - n B isA- xB- 3 xD- x-3

The correct option is A x n (A̅∩B̅) =Shaded area n (A̅∩B̅) = x n(A∪ B) So, n(A)+n(B) = x. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

s- Block Elements

If there are ...

Question

If there are two sets A and B such that $n (¯ A \cap ¯ B) = n (A \cap B)$ . Universal set contains 'x' elements. Then n (A) + n (B) is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
x

$n (¯ A \cap ¯ B) =$ Shaded area
$n (¯ A \cap ¯ B) = x - n (A \cup B)$
So, n(A)+n(B) = x.

Suggest Corrections

Similar questions

Q. If

U

is the universal set with 100 element;

A

and

B

are two set such that

n (A) = 50, n (B) = 60, n (A \cap B) = 20

, then

n (A^{'} \cap B^{'}) =

Let U be the universal set containing 700 elements. If A, B are sub-sets of U such that n (A) = 200, n(B) =300 and $n (A \cap B)$ = 100. Then , $n (A^{'} \cap B^{'}) =$

Q. If

U

is the universal set with 100 element;

A

and

B

are two set such that

n (A) = 50, n (B) = 60, n (A \cap B) = 20

, then

n (A^{'} \cap B^{'}) =

Q. If

A

and

B

are two sets and

U

is the universal set such that

n (U) = 700, n (A) = 200, n (B) = 300

and

n (A \cap B) = 100

, find

n (A^{'} \cap B^{'})

Q. If

A

and

B

are two sets such that

n (A) = 3

and

n (B) = 5,

then

n (A \times B) =

Join BYJU'S Learning Program

If there are two sets A and B such that n(¯A∩¯B)=n(A∩B). Universal set contains 'x' elements. Then n (A) + n (B) is

The correct option is A x n(¯A∩¯B)=Shaded area n(¯A∩¯B)=x−n(A∪B) So, n(A)+n(B) = x.

If there are two sets A and B such that $n (¯ A \cap ¯ B) = n (A \cap B)$ . Universal set contains 'x' elements. Then n (A) + n (B) is

The correct option is A
x

$n (¯ A \cap ¯ B) =$ Shaded area
$n (¯ A \cap ¯ B) = x - n (A \cup B)$
So, n(A)+n(B) = x.