If there exists a gravitational force of $2 \times 10^{20} N$ between the Earth and the Moon, find the mass of Earth. Take mass of the moon as $7.4 \times 10^{22} k g$ .

3 \times 10^{24} k g

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6 \times 10^{27} k g

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6 \times 10^{34} k g

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3 \times 10^{30} k g

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Solution

The correct option is B $6 \times 10^{27} k g$
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Define gravitational mass. The mass of the earth is $6 \times 10^{24} k g$ and that of the moon is $7.4 \times 10^{22} k g$ . If the distance between the earth and the moon be $3.84 \times 10^{5} k m$ , calculate the force exerted by the earth on the moon. $(G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2})$
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Q. The mass of the earth is

6 \times 10^{24}

kg and that of the moon is

7.4 \times 10^{22}

kg. If the distance between the earth and the moon is 3.8

\times 10^{5}

km. calculate the force exerted by the earth.

The mass of the earth is $6 \times 10^{24}$ kg and that of the moon is $7.4 \times 10^{22}$ kg. If distance between the earth and the moon be $3.84 \times 10^{5}$ km, calculate the force exerted by the earth on the moon. $(G = 6.7 \times 10^{- 11} N m^{2} k g^{- 2})$ .

A rocket is fired from the earth towards the moon. At what distance from the moon is the gravitational force on the rocket zero? Mass of earth = 6 x 10²⁴ kg and Mass of moon = 7.4 x 10²² kg and orbital radius of the moon= 3.8 x 10⁸ m. Neglect the effect of the sun and the other planets.

Q. Imagine that the gravitational force between Earth and Moon is provided by an invisible string that exists between the Moon and Earth. What is the tension that exists in this invisible string due to Earth's centripetal force?(Mass of the Moon

= 7.34 \times 10^{22}

kg, Distance between Moon and Earth

= 3.84 \times 10^{8}

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If there exists a gravitational force of 2×1020 N between the Earth and the Moon, find the mass of Earth. ​Take mass of the moon as 7.4×1022 kg.

The correct option is B 6×1027 kg--

If there exists a gravitational force of $2 \times 10^{20} N$ between the Earth and the Moon, find the mass of Earth. Take mass of the moon as $7.4 \times 10^{22} k g$ .

The correct option is B $6 \times 10^{27} k g$
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