If there is a positive error of 50 ?/? in the measurement of velocity of a body, then error in measurement of kinetic energy is?

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Solution

$∆ v = 50 S o t h e e r r o r i n t h e m e a s u r e m e n t o f K . E . = 2 \times ∆ v = 2 \times 50 = 100$

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If there is a positive error of 50 ?/? in the measurement of velocity of a body, then error in measurement of kinetic energy is?

∆v=50So the error in the measurement of K. E. =2×∆v=2×50=100

$∆ v = 50 S o t h e e r r o r i n t h e m e a s u r e m e n t o f K . E . = 2 \times ∆ v = 2 \times 50 = 100$