You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Dalton's Law of Partial Pressures

If there unre...

Question

If there unreactive gases having partial pressure $P_{A}, P_{B}$ and $P_{C}$ and there moles are $1, 2$ and $3$ respectively then their total pressure will be :

P = P_{A} + P_{B} + P_{C}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P = \frac{P_{A} + P_{B} + P_{C}}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = \frac{\sqrt{P_{A} + P_{B} + P_{C}}}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $P = P_{A} + P_{B} + P_{C}$
According to Dalton's law of partial pressure,

Total pressure = sum of partial pressures of individual gases

$P_{t o t a l} = P_{a} + P_{b} + P_{c}$

Therefore, option A is correct.

Suggest Corrections

Similar questions

In the following diagram $P_{A}, P_{B}, P_{C}, P_{D} a n d P_{E}$ be the pressure exerted by the liquid in the vessels A, B, C, D and E respectively. Find the correct order of pressure exerted by each vessel.

Q. Water is flowing through a channel (lying in a vertical plane) as shown in the figure. Three sections

A, B

and

C

are shown. Section

B

and

C

have equal areas of cross- section. If

P_{A}, P_{B}

and

P_{C}

are the pressures at

A, B

and

C

respectively, then

Q. An object of uniform density is allowed to float in water kept in a beaker. The object has triangular cross-section as shown in the figure. If the water pressure measured at the three points

A, B

and

C

below the object are

P_{A}, P_{B}

and

P_{C}

respectively, then:

Q. If

A, B, C

are three events, then show that

P (A \cup B \cup C) = P (A) + P (B) + P (C) - P (A \cap B) - P (B \cap C) - P (C \cap A) + P (A \cap B \cap C)

Q. If P is a point in the interior of ∆ABC then fill in the blanks with > or < or =.

(i) PA + PB ...... AB
(ii) PB + PC ...... BC
(iii) AC ...... PA + PC

Join BYJU'S Learning Program

If there unreactive gases having partial pressure PA,PB and PC and there moles are 1,2 and 3 respectively then their total pressure will be :

The correct option is A P=PA+PB+PCAccording to Dalton's law of partial pressure,Total pressure = sum of partial pressures of individual gasesPtotal=Pa+Pb+PcTherefore, option A is correct.

If there unreactive gases having partial pressure $P_{A}, P_{B}$ and $P_{C}$ and there moles are $1, 2$ and $3$ respectively then their total pressure will be :

The correct option is A $P = P_{A} + P_{B} + P_{C}$
According to Dalton's law of partial pressure,

Total pressure = sum of partial pressures of individual gases

$P_{t o t a l} = P_{a} + P_{b} + P_{c}$

Therefore, option A is correct.