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Dalton's Law of Partial Pressures

If there unre...

Question

If there unreactive gases having partial pressure $P_{A}, P_{B}$ and $P_{C}$ and there moles are $1, 2$ and $3$ respectively then their total pressure will be :

P = P_{A} + P_{B} + P_{C}

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P = \frac{P_{A} + P_{B} + P_{C}}{6}

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P = \frac{\sqrt{P_{A} + P_{B} + P_{C}}}{3}

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None of these

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Solution

The correct option is A $P = P_{A} + P_{B} + P_{C}$
According to Dalton's law of partial pressure,

Total pressure = sum of partial pressures of individual gases

$P_{t o t a l} = P_{a} + P_{b} + P_{c}$

Therefore, option A is correct.

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If there unreactive gases having partial pressure PA,PB and PC and there moles are 1,2 and 3 respectively then their total pressure will be :

The correct option is A P=PA+PB+PCAccording to Dalton's law of partial pressure,Total pressure = sum of partial pressures of individual gasesPtotal=Pa+Pb+PcTherefore, option A is correct.

If there unreactive gases having partial pressure $P_{A}, P_{B}$ and $P_{C}$ and there moles are $1, 2$ and $3$ respectively then their total pressure will be :

The correct option is A $P = P_{A} + P_{B} + P_{C}$
According to Dalton's law of partial pressure,

Total pressure = sum of partial pressures of individual gases

$P_{t o t a l} = P_{a} + P_{b} + P_{c}$

Therefore, option A is correct.