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Electric Field Due to Charge Distributions - Approach

If there were...

Question

If there were only one type of charge in the universe, then

\oint_{s} \to E . d \to s \neq 0

on any surface

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\oint_{s} \to E . d \to s = 0

if the charge is outside the surface

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\oint_{s} \to E . d \to s = \frac{q}{ε_{0}}

if charges of magnitude

q

were inside the surface

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both (b) and (c) are correct

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Solution

The correct option is A both (b) and (c) are correct
According to Gauss's theorem in electrostatics
$\oint \to E . d \to s = \frac{q}{ε_{0}}$
Here $q$ is charge enclosed by the surface
If the charge is outside the surface, therefore $q_{i n s i d e} = 0$
Also, $\oint \to E . d \to s = 0$
So (b) and (c) are correct

Suggest Corrections

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\oint_{s} \to E . \to d s = 0

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\int E . d s = 0

\oint \to E . \to d s = \frac{q_{0}}{ε_{0}}

\oint \to B . \to d s = 0

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