Question

If there were three possible values for spin quantum number $(+\frac{1}{2},0,-\frac{1}{2})$ rather than two. Which of the following is/are correct regarding a hypothetical period table based on this condition?

• A. First period would have only 2 vertical columns
• B. Second period would have 12 elements
• C. Periodic table would contain 27 groups
• D. Third period would have 12 elements

Answer 1

Answer: (B), (C), (D)

Periodic table would contain 27 groups
Second period would have 12 elements
Third period would have 12 elements

After this hypothetical condition, every orbital can have 3 electron.
As in second orbit, 4 orbital are there so total no. of electron is $4\times 3=12$.
Second period would have 12 elements.
Third period would have 12 elements.
Periodic table would contain $18\times 3/2=27$ groups.