Question

If ${\theta }^c=-\frac{5{\pi }^c}{9}$ and ${\varphi }^0={900}^0,$ find ${\theta }^o$ and ${\varphi }^c$

Answer 1

${\theta }^c=-\frac{5{\pi }^c}{9}$ $\theta \in [0,2\pi ]\to Standard$ ,$\theta \in [0,{360}^{\circ }]\to Standard$

$\therefore {\theta }^c=2\pi -\frac{5\pi }{9}$

$\therefore {\theta }^c=\frac{13{\pi }^c}{9}$

${\varphi }^{\circ }={900}^{\circ }$

$Standard{\varphi }^{\circ }={900}^{\circ }-{720}^{\circ }$

$={180}^{\circ }$

$\therefore Standard{\theta }^c=\frac{13{\pi }^c}{9},Standard{\varphi }^{\circ }={180}^{\circ }$