If ′θ′ is the angle between the lines ax2+2hxy+by2=0, then angle between x2+2xysecθ+y2=0 is
A
θ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
θ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Aθ Angle between the lines ax2+2hxy+by2=0 is tanθ=∣∣∣2√h2−aba+b∣∣∣ For x2+2xysecθ+y2=0 h=secθ,a=b=1 ∴tanϕ=∣∣∣2√sec2θ−11+1∣∣∣ =2tanθ2=tanθ ∴ Angle between x2+2xysecθ+y2=0 is θ.