Question

If $\theta$ is the polarizing angle for a medium in which the speed of light is $v$, then according to Brewster's Law :

• A. $\theta ={\sin }^{-1}\left(c/v\right)$
• B. $\theta ={\tan }^{-1}\left(c/v\right)$
• C. $\theta ={\cos }^{-1}\left(c/v\right)$
• D. $\theta ={\sin }^{-1}\left(v/c\right)$

Answer 1

The correct option is B $\theta ={\tan }^{-1}\left(c/v\right)$

Brewster's Angle is given by:

$\theta ={\tan }^{-1}\left(n\right)$

where $n:$ Refractive index of the medium.

From definition of refractive index,

$n=\frac{c}{v}$

Hence, $\theta ={\tan }^{-1}\left(c/v\right)$