Question

If $\theta \le x\le \pi$; then the area bounded by the curve $y=x$ and $y=x+\sin x$ is

• A. $2$
• B. $4$
• C. $2\pi$
• D. $4\pi$

Answer 1

The correct option is A $2$

$A={\int }_0^{\pi }x+\sin x-xdx$

$A={\int }_0^{\pi }\sin xdx$

$A={[-\cos x]}_0^{\pi }$

$A=-cos\pi -cos0$

$a=1-(-1)=2$