wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If θϕ=π/2, then show that [cos2θcosθsinθcosθsinθsin2θ][cos2φcosφsinφcosφsinφsin2φ]=0

Open in App
Solution

[cos2θcosθsinθcosθsinθsin2θ][cos2θcosθsinθcosθsinθsin2θ]=[cos2θcosθsinθcosθsinθsin2θ]cos2(θπ2)cos(θπ2)sin(θπ2)cos(θπ2)sin(θπ2)sin2(θπ2)=[cos2θsinθcosθsinθcosθsin2θ][sin2θsinθcosθsinθcosθcos2θ]=[sin2θcos2θsin2θcos2θsinθcos3θ+sinθcos3θsin3θcosθsin2θcosθsin2θcosθ+sin2θcos2θ]=[0000]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Multiplication of Matrices
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon