wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If θ=sin1x+cos1xtan1x,1x<, then the smallest interval in which θ lies is

A
π2θ3π4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0θπ4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
π4θ0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π4θπ2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0θπ4
Given, θ=sin1x+cos1xtan1x
= π2 -tan1x because sin1x +cos1x = π2 = tan1(x)
θ=cot1x
Since, 1x<, therefore 0θ<π4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Inverse Trigonometric Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon