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Question

If this pattern continues, where would the number 289 appear?.


A

Row 17

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B

Row 18

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C

Row 19

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D

Row 20

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Solution

The correct option is A

Row 17


Perfect squares are the middle term of odd rows. (17)2=289 should be middle term of 17th row. Option (a).

Alternate Solution:

There is 1 odd number in the 1st row.

There are 2 odd numbers in the 2nd row.

There are 3 odd numbers in the 3rd row. ...

Hence this can be considered as an question where, n is the number of odd numbers.

As 289 will be 2892=144145th term in the sequence, find an value which is close to the number. which is equal to 153 and 17 numbers before 153 will be in the 17th row. Hence the answer is 17.


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