If this pattern continues, where would the number 289 appear?.
Row 17
Perfect squares are the middle term of odd rows. (17)2=289 should be middle term of 17th row. Option (a).
Alternate Solution:
There is 1 odd number in the 1st row.
There are 2 odd numbers in the 2nd row.
There are 3 odd numbers in the 3rd row. ...
Hence this can be considered as a∑n question where, n is the number of odd numbers.
As 289 will be 2892=144145th term in the sequence, find a∑n value which is close to the number. which is equal to 153 and 17 numbers before 153 will be in the 17th row. Hence the answer is 17.