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Question
If three angles of a triangle are in the ratio 2: 3: 5, determine three angles.
If three angles of a triangle are in the ratio 2: 3: 5, determine three angles.
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Solution
Given: ∠A: ∠B: ∠C = 2x: 3x: 5x
To Find: ∠A, ∠B and ∠C
Solution:
In ΔABC, ∠A + ∠B + ∠C = 180° (Sum of the angles of a triangle)
2x + 3x + 5x = 180°
10x = 180°
∴x = 18°
∠A = 2x = 36°
∠B = 3x = 54°
∠C =5x = 90°
Given: ∠A: ∠B: ∠C = 2x: 3x: 5x
To Find: ∠A, ∠B and ∠C
Solution:
In ΔABC, ∠A + ∠B + ∠C = 180° (Sum of the angles of a triangle)
2x + 3x + 5x = 180°
10x = 180°
∴x = 18°
∠A = 2x = 36°
∠B = 3x = 54°
∠C =5x = 90°
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