Question

If three angles of quadrilateral are each equal to ${75}^{\circ }$ , the fourth angle is

Answer 1

The sum of the angles of a quadrilateral $={360}^0$

Given, three of the angles are ${75}^0$ each

$\therefore$ Let the fourth angle be $x$

$\therefore$ $3\times {75}^0+x={360}^0$

$x={360}^0-{225}^0$

$x={135}^0$