If three coins are tossed simultaneously
a) Write all possible outcomes
b) Number of possible outcomes
c) Find the probability of getting at least one head
(getting one or more than one head)
d) Find the probability of getting at most two heads
(getting two or less than two heads)
e) Find the probability of getting no tails.

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Solution

In tossing three coins, the sample space is given by
{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
(a) Then all possible outcomes are =8
(b) Then number of possible outcomes=8
(c)Then the probability of getting at least one head= $\frac{n u m b e r o f p o s s i b l e o u t c o m e s o f o n e h e a d s}{n u m b e r o f t o t a l p o s s i b l e o u t c o m e s} = \frac{3}{8}$
(d)Then the probability of getting at least two heads= $\frac{n u m b e r o f p o s s i b l e o u t c o m e s o f t w o h e a d s}{n u m b e r o f t o t a l p o s s i b l e o u t c o m e s} = \frac{3}{8}$
(e)Then the probability of getting no tail= $\frac{n u m b e r o f p o s s i b l e o u t c o m e s o f n o t a i l}{n u m b e r o f t o t a l p o s s i b l e o u t c o m e s} = \frac{1}{8}$

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