wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If three connective vertices of a parallelogram ABCD are A(1,2),B(3,6) and C(5,10), find its fourth vertex D.

Open in App
Solution

The vertices of a parallelogram ABCD are
A=(1,2)

B=(3,6)

C=(5,10)

Let, the fourth vertex be D=(x,y) then,

Mid-point of diagonal AC= Mid-point of diagonal BD

(1+52,2+102)=(3+x2,6+y2)

(3,4)=(3+x2,6+y2)

3+x2=3 and 6+y2=4

3+x=6 and 6+y=8

x=3 and y=2

The fourth vertex D=(3,2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Mid-Point Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon