If three consecutive coefficients in the expansion of (1+x)n be 165, 330 and 462, then nC2 =
55
66
45
does not exist
nCr−1 = 165, nCr = 330, nCr+1 = 462
⇒ rn−r+1 = 12, r+1n−r = 57 ⇒ n = 11.
∴ nC2 = 11C2 = 11×102 = 55.
The coefficients of three successive terms in the expansion of (1+x)n are 165, 330 and 462 respectively, then the value of n will be
The coefficients of three successive terms in the
expansion of (1+x)n are 165, 330 and 462
respectively, then the value of n will be