Question

If three consecutive term of an ap are

2K,K+4,3K+5. FIND THE VALUES OF K AND WRITE THE

AP

Answer 1

If three consecutive term of an ap are

2K,K+4,3K+5, then their common difference is same i.e t2-t1=t3-t2
here t1=2K
t2=K+4
t3=3K+5
as per question,
K+4 - 2K = 3K+5 - (K+4)
4-K = 3K+5 -K -4
4-K = 2K +1
4-1 = 2K+K
3K =3
K=1
therefore ap is 2K,K+4,3K+5
i.e 2,(1+4),(3+5), i.e 2,5,8