Question

If three cubes of metal whose edges are $6$ cm, $8$ cm and $10$ cm are melted and made into a single cube, then the edge of the new cube so formed will be;

• A. $6$ cm
• B. $8$ cm
• C. $12$ cm
• D. $24$ cm

Answer 1

The correct option is C $12$ cm

Given cubes of side lengths $6$ cm, $8$ cm, $10$ cm.

Volume remains same so volume of new cube = sum of volumes of three cubes= v1+v2+v3

$=6^3+8^3+{10}^3$
$=216+512+1000$
$=1728$
Now volume of new cube $=a^3=1728=(12{)}^3$
Edge of new cube $=a=12$.