If three geometric means are inserted between 2 and 32, then the third geometric mean will be
16
Let 2,g1,g2,g3, 32 be the required series. then,
a=2, ar=g1,ar2=g2,ar3=g3 and ar4=32
Now 2 × r4=32⇒r4=16
⇒(2)4=16=(2)4⇒r=2.
Then third geometric mean ar2=2×23=16.