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Question

If three geometric means be inserted between 2 and 32, then the third geometric mean will be

A

8

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B

4

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C
16
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D
12
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Solution

The correct option is C 16
2,g1,g2,g3, 32 where

a=2, ar=g1,ar2=g2,ar3=g3andar4=32
Now 2 × r4=32r4=16=(2)4=16=(2)4r=2.
Then third geometric mean ar2=2×23=16.

Aliter : By formula, G3=2.(322)3/4=2.8=16.


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