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Question

If three lines whose equations are concurrent, then show that

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Solution

The equation of given lines is,

y= m 1 x+ c 1 (1)

y= m 2 x+ c 2 (2)

y= m 3 x+ c 3 (3)

Subtract equation (1) from equation (2).

0=( m 2 m 1 )x+( c 2 c 1 ) ( m 2 m 1 )x=( c 2 c 1 ) x= ( c 2 c 1 ) ( m 2 m 1 ) x= ( c 2 c 1 ) ( m 1 m 2 )

Substitute the value of x in equation (1).

y= m 1 × ( c 2 c 1 ) ( m 1 m 2 ) + c 1 = m 1 c 2 m 1 c 1 m 1 m 2 + c 1 = m 1 c 2 m 1 c 1 + c 1 ×( m 1 m 2 ) m 1 m 2 = m 1 c 2 m 1 c 1 + c 1 m 1 c 1 m 2 m 1 m 2

Further solve the above expression.

y= m 1 c 2 m 2 c 1 m 1 m 2

The coordinate of the point of intersection of line (1) and line (2) is ( c 2 c 1 m 1 m 2 , m 1 c 2 m 2 c 1 m 1 m 2 ).

It is given in the question that line (1), line (2) and line (3) are concurrent.

Thus, the point ( c 2 c 1 m 1 m 2 , m 1 c 2 m 2 c 1 m 1 m 2 ) will also satisfy the equation of line (3).

Substitute the value of point in equation of line (3).

m 1 c 2 m 2 c 1 m 1 m 2 = m 3 c 2 c 1 m 1 m 2 + c 3 m 1 c 2 m 2 c 1 m 1 m 2 = m 3 c 2 m 3 c 1 + c 3 ( m 1 m 2 ) m 1 m 2 m 1 c 2 m 2 c 1 = m 3 c 2 m 3 c 1 + c 3 m 1 c 3 m 2 m 1 c 2 m 2 c 1 m 3 c 2 + m 3 c 1 c 3 m 1 + c 3 m 2 =0

Further simplify the above expression.

m 1 ( c 2 c 3 )+ m 2 ( c 3 c 1 )+ m 3 ( c 1 c 2 )=0

Hence, the condition for the three lines y= m 1 x+ c 1 , y= m 2 x+ c 2 , and y= m 3 x+ c 3 to be concurrent is m 1 ( c 2 c 3 )+ m 2 ( c 3 c 1 )+ m 3 ( c 1 c 2 )=0.


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