If three six faced die each marked with numbers 1 to 6 on six faces, the thrown find the total number of possible outcomes.
Total numbers of faces in each die= 6 ∴ the total number of possible outcomes of three six faced die = 6×6×6=216
Six faces of a die are marked with number 1,−1,0,−2,2,3, and the die is thrown thrice. The probability that the sum of the numbers thrown is six, is