If three times the first of three consecutive odd integers is 3 more than twice the third then the third integer is

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Solution

The correct option is D 15
Let the three integers be $x, x + 2$ & $x + 4$
$3 x = 2 (x + 4) + 3$
$\Rightarrow x = 11$
$∴$ Third integer $= x + 4 = 15$

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