Question

If three unbiased dice are thrown simultaneously, then what is the probability of getting at least one six on the dices?

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Find the number of cases in which none of the digits show a '6'.

i.e. all three dice show a number other than '6', 5$\times$5$\times$5 = 125 cases.

Total possible outcomes when three dice are thrown = 216.

The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.

= 216−125 = 91

$\therefore$ Required probability =$\frac{91}{216}$