If threshold frequency of a metal surface is 7×1014 Hz, find the work function of the metal.
Work function = ϕ0=hf0e
ϕ0=6.63×10−34×7×10141.6×10−19
ϕ0=2.896 eV≈2.9 eV
Hence, (C) is the correct answer.
Why this question? concept: ϕ0=hf0 --(in J) work function: ϕ0=hf0e ---(in eV) |