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Question

If threshold frequency of a metal surface is 7×1014 Hz, find the work function of the metal.

A
2.2 eV
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B
4.6 eV
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C
2.9 eV
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D
9.2 eV
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Solution

The correct option is C 2.9 eV

Work function = ϕ0=hf0e

ϕ0=6.63×1034×7×10141.6×1019

ϕ0=2.896 eV2.9 eV

Hence, (C) is the correct answer.

Why this question?
concept: ϕ0=hf0 --(in J)
work function: ϕ0=hf0e ---(in eV)

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