Question

If time of flight of a projectile is 10 seconds and range is $500m$. Then what will be the maximum height attained by it?
Take $g=10m/s^2$.

• A. $125m$
• B. $50m$
• C. $100m$
• D. $150m$

Answer 1

The correct option is A $125m$

$T=\frac{2u\sin \theta }{g}=10\sec \Rightarrow u\sin \theta =50m/sH=\frac{u^2{\sin }^2\theta }{2g}=\frac{(u\sin \theta {)}^2}{2g}H=\frac{50\times 50}{2\times 10}=125m$