Question

If time of flight of a projectile is 10 seconds. Range is 500 m. The maximum height attained by it will be

• A. 125 m
• B. 50 m
• C. 100 m
• D. 150 m

Answer 1

The correct option is A 125 m

$T=\frac{2usin\theta }{g}=10sec\Rightarrow usin\theta =50soH=\frac{u^{2}si{n}^2\theta }{2g}=\frac{(50{)}^2}{2\times 10}=125m$