Question

If time of flight of a projectile is 10 seconds. Range is 500 meters. The maximum height attained by it will be

• A. 125 m
• B. 50 m
• C. 100 m
• D. 150 m

Answer 1

The correct option is A

125 m

$T=\frac{2usin\theta }{g}=10sec\Rightarrow usin\theta =50m/s$
$\therefore H=\frac{u^{2}si{n}^2\theta }{2g}=\frac{(usin\theta {)}^2}{2g}=\frac{50\times 50}{2\times 10}=125m$