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Question

If △1=∣∣ ∣ ∣∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2+c1b22+c2b2b3+c3c3c1c3c2c23∣∣ ∣ ∣∣ and △2=∣∣ ∣∣a1b1c1a2b2c2a3b3c3∣∣ ∣∣, then △1△2 is equal to

A
a1b2c3
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B
a1a2a3
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C
a3b2c1
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D
a1b1c1+a2b2c2+a3b3c3
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Solution

The correct option is A a1b2c3
1=∣ ∣ ∣a21+b1+c1a1a2+b2+c2a1a3+b3+c3b1b2+c1b22+c2b2b3+c3c3c1c3c2c23∣ ∣ ∣
=∣ ∣ ∣a21a1a2a1a3b1b2b22b2b3c3c1c3c2c23∣ ∣ ∣+∣ ∣b1+c1b2+c2b3+c3c1c2c3000∣ ∣
=a1b2c3∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣+∣ ∣b1+c1b2+c2b3+c3c1c2c3000∣ ∣
=a1b2c3∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣+∣ ∣b1b2b3c1c2c3000∣ ∣+∣ ∣c1c2c3000000∣ ∣
=a1b2c3∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣+0+0
=a1b2c3∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣
Given 2=∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣
12=a1b2c3∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣∣ ∣a1a2a3b1b2b3c1c3c3∣ ∣
=a1b2c3

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