The correct options are
A AO = BO = CO
C △AOC≅ △COB≅ △BOA
Given: AO, BO, CO are angle bisectors,
△ABC is equilateral⇒each angle is equal to 60°.
In △AOC,△COB,△BOA
∠OAC=∠OAB=30° ( AO is the angle bisector)
Similarily ∠ABO=∠CBO=30°
∠ACO=∠OCB=30°
AC = CB = BA .... (Equilateral triangle - given)
So, by ASA criteria,
△AOC≅ △COB≅ △BOA
⇒AO=BO=CO .... (corresponding parts of congruent triangles)