If $△ A B C$ is an obtuse angled triangle in which $< C = 110^{0}$ then which one of the following is true-

A B = A C

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A B < A C

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A B > A C

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A B < B C

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Solution

The correct option is C $A B > A C$
Here , $< C = 110^{0}$
$\Rightarrow$ < Aand < B are acute angles
$\Rightarrow$ <C > < B\therefore$ AB > AC

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Question 37

In a right angled $Δ A B C$ , if $∠ B = 90^{\circ}$ , then which of the following is true?

a) $A B^{2} = B C^{2} + A C^{2}$
b) $A C^{2} = A B^{2} + B C^{2}$
c) $A B = B C + A C$
d) $A C = A B + B C$

A B C,

A B = A C

∠ B = ∠ C

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