If $△ A B C \sim △$ DEF such that AB = 12 cm and DE = 14 cm. Find the ratio of areas of $△$ ABC and $△$ DEF.

$\frac{25}{49}$

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$\frac{49}{16}$

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$\frac{36}{49}$

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$\frac{49}{9}$

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Solution

The correct option is C
$\frac{36}{49}$

We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides,

$\frac{a r e a o f △ A B C}{a r e a o f △ D E F} = {(\frac{A B}{D E})}^{2} = {(\frac{12}{14})}^{2} = \frac{36}{49}$

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Similar questions

If $△ A B C \sim △$ DEF such that AB = 12 cm and DE = 14 cm. Find the ratio of areas of $△$ ABC and $△$ DEF.

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