If $△$ ACD is congruent to $△$ BDC, then side of $△$ BDC corresponds to the side AC.

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Solution

The correct option is C BD
In the two triangles, $△$ ACD and $△$ BDC,
side DA = side CB = 4cm
hypotenuse CD = hypotenuse DC = 8cm
$∠$ CAD = $∠$ CBD = 90°

$∴$ $△$ ACD $≅ △$ BDC by RHS criterion for congruency of triangles
So, BD = AC (corresponding parts of congruent triangles.)

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