Question

If $△$ACD is congruent to $△$BDC, then which side of $△$BDC corresponds to side AC?

• A. CB
• B. DC
• C. BD
• D. None of the above

Answer 1

The correct option is C BD


In the two triangles, $△$ACD and $△$BDC,
side DA = side CB = 4cm
hypotenuse CD = hypotenuse DC = 8cm
$\angle$CAD = $\angle$CBD = 90°

$\therefore$ $△$ACD $\cong △$BDC by RHS criterion for congruency of triangles
So, BD = AC (corresponding parts of congruent triangles.)