CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

If =∣ ∣ ∣axx21byy21czz21∣ ∣ ∣ and
1=∣ ∣abcxyzyzzxxy∣ ∣, then which of the following is correct

A
1+=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
12=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1=0
Given : 1=∣ ∣abcxyzyzzxxy∣ ∣
Taking transpose of above determinant, we get
1=∣ ∣axzybyzxczxy∣ ∣
Now multiplying R1 by x, R2 by y and R3, by z,we get
1=1xyz∣ ∣ ∣axx2xzybyy2xyzczz2xyz∣ ∣ ∣
Taking xyz common from C3, we get
1=xyzxyz∣ ∣ ∣axx21byy21czz21∣ ∣ ∣=
1=0

flag
Suggest Corrections
thumbs-up
1
BNAT
mid-banner-image