If △ DEF ∼ △ABC, AB = 4 cm, BC = 4 cm, CA = 3 cm and EF = 2 cm, then the perimeter of △DEF is ____ cm.
Given △ DEF ∼ △ABC.
⇒ABDE=ACDF=BCEF
4DE=3DF=42 ⇒4DE=2 and 3DF=2
⇒DE=2 cm and DF=1.5 cm
Perimeter of △ DEF = DE + EF+ FD
= 2 cm + 2 cm + 1.5 cm
= 5.5 cm