Question

If $△G$ for the reaction is $A^{+}+B^{-}\to A^{2+}+B^{2-}$ is X , the $△G$ for the reaction is:

$\frac{1}{2}{A}^{+}+\frac{1}{2}{B}^{-}\to \frac{1}{2}{A}^{2+}+\frac{1}{2}{B}^{2-}$

• A. $\frac{X}{2}$
• B. 2X
• C. $X^2$
• D. $\sqrt{X}$

Answer 1

The correct option is A $\frac{X}{2}$

We know that,

$\Delta G=-nF{E}_{cell}$

For the given reaction, $A^{+}+B^{-}\to A^{2+}+B^{2-}$ the $\Delta G$ is given as X.

So, for $\frac{1}{2}{A}^{+}+\frac{1}{2}{B}^{-}\to \frac{1}{2}{A}^{2+}+\frac{1}{2}{B}^{2-}$

Now the value of n changes to $n=\frac{1}{2}$

Hence, the value of $\Delta G$ becomes half of the first value and hence it becomes $\frac{X}{2}$