If true enter 1, else enter 0.
Following reaction is disproportionation reaction:
${N H}_{4}^{+} + {N O}_{3}^{-} ⟶ N_{2} O + 2 H_{2} O$
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Solution

The correct option is A 0
The redox reaction ${N H}_{4}^{+} + {N O}_{3}^{-} ⟶ N_{2} O + 2 H_{2} O$ is not a disproportionation reaction. In a disproportionation reaction, one molecule of an element is oxidized and other molecule of same element is reduced.

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