If true enter 1, else enter 0. HCHO disproportionates in presence of OH−.
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Solution
The correct option is A 1 In presence of a base, the formaldehyde disproportionates into formic acid and methanol. 2HCHO+OH−→HCOO−+HCH2OH Thus, formaldehyde is oxidized to formic acid and reduced to methanol.